Question

What is the freezing point of a 0.800m aqueous solution of glucose, given that Kf for water is 1.86°C/m? Show your work.

Answer 1

To determine the freezing point we can apply the following formula that relates the molality to the freezing point of water:

$\Delta T_f=K_f\times m$

Where,

m is the molality

Kf is the freezing point of water

DeltaTf= Freezing point

We replace the known data:

$\Delta T_f=1.86\frac{\degree C}{m}\times0.800m=1.49\degree C$

So, the freezing point of the solution will be 1.49°C