start by replacing x from the first equation into the second equation
[tex]5y-13=-3y+19[/tex]solve the equation for y
[tex]\begin{gathered} 5y+3y=19+13 \\ 8y=32 \\ y=\frac{32}{8} \\ y=4 \end{gathered}[/tex]replace y into the first equation to find x
[tex]\begin{gathered} x=5\cdot(4)-13 \\ x=20-13 \\ x=7 \end{gathered}[/tex]the solution for the system of equations is (7,4).