Question

Constuct the indicated confidence for thr population mean using the t distribution assume the population is normally distributed c= 0.99,x bar 13.2, s=4.0,n 8

Answer 1

First, let's use the following formula about the margin error.

$ME=\frac{z\cdot\sigma}{\sqrt[]{n}}$

But, we use n to find the degrees of freedom.

$df=n-1=8-1=7$

Using a calculator, we get a critical value t-score of 3.5.

Now we can find the margin error.

$ME=\frac{3.5\cdot4}{\sqrt[]{8}}\approx4.95$

Then, we form the confidence interval using the mean.

[tex]\begin{gathered} 13.2-4.95

Therefore, the confidence interval is 8.25 < m < 18.15.