Respuesta :

Given,

The initial velocity of the Bugatti Veyron, u=0 m/s

The final velocity of the car, v= 124 m/s

The time period in which the car accelerated from rest to the given speed, t=3.7 s

The acceleration of an object is the rate of change of velocity over an interval of time.

Thus the acceleration is given by,

[tex]a=\frac{v-u}{t}[/tex]

On substituting the known values,

[tex]\begin{gathered} a=\frac{124-0}{3.7} \\ =33.5m/s^2 \end{gathered}[/tex]

Thus the acceleration of the car is 33.5 m/s²

ACCESS MORE
EDU ACCESS