Question

state the minimum value of f(x) = 3x^2 + 6x - 2

Answer 1

Answer:

Explanation:

Given:

$f(x)=3x^2+6x-2$

There are ways to find the minimum value of the given function. We graph it or express it into vertex form:

For the graph:

Based on the graph, the lowest point is at (-1,-5).

We can double check this by expressing it into vertex form:

$\begin{gathered} 3x^2+6x-2\text{ = }3(x+1)^2-5 \\ \text{where:} \\ h=-1 \\ k=-5 \\ or \\ (-1,-5) \end{gathered}$

Therefore, the minimum value is (-1,-5)