The equation of the line in Slope-Intercept form is:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
So, we must write each equation in Slope-Intercept form. We can do that solving for "y".
For Equation 1:
[tex]\begin{gathered} 7x-y=34 \\ 7x-34=y \\ y=7x-34 \end{gathered}[/tex]We can see that:
[tex]\begin{gathered} m=7 \\ y=-34 \end{gathered}[/tex]Knowing those values, we can graph the line.
For Equation 2:
[tex]\begin{gathered} 2x+3y=-10 \\ 3y=-2x-10 \\ y=-\frac{2}{3}x-\frac{10}{3} \end{gathered}[/tex]For this line:
[tex]\begin{gathered} m=-\frac{2}{3} \\ b=-\frac{10}{3} \end{gathered}[/tex]Knowing those values, we can graph the second line.
See the graph attached.
Observe that they intersect each other at the point (4,-6). That point of intersection is the solution of the System of equations:
[tex]\begin{gathered} x=4 \\ y=-6 \end{gathered}[/tex]