Respuesta :

Given equation:

[tex]9x^2-6x+1=0[/tex]

By using middle term factirization we get,

[tex]\begin{gathered} 9x^2-6x+1=0 \\ 9x^2-3x-3x+1=0 \\ 3x(3x-1)-1(3x-1)=0 \\ (3x-1)(3x-1)=0 \end{gathered}[/tex][tex]\begin{gathered} (3x-1)^2=0 \\ x=\frac{1}{3},\frac{1}{3} \end{gathered}[/tex]

So, the roots are real and same.

Thus, the equation have a repeated real rools.

Answer: Option (A)

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