A bag contains 2 gold marbles, 8 silver marbles, and 26 black marbles. Someone offers to play this game: Yourandomly select one marble from the bag. If it is gold, you win $3. If it is silver, you win $2. If it is black, youlose $1.What is your expected value if you play this game?

Respuesta :

The first step is to find the probability for each of the events, which are pick up a gold marble, pick up a silver marble and pick up a black marble:

[tex]\begin{gathered} P(G)=\frac{2}{36}=\frac{1}{18} \\ P(S)=\frac{8}{36}=\frac{2}{9} \\ P(B)=\frac{26}{36}=\frac{13}{18} \end{gathered}[/tex]

Now, multiply each of the probabilities by its corresponding reward and find the sum of them to find the expected value:

[tex]\begin{gathered} E=3\cdot\frac{1}{18}+2\cdot\frac{2}{9}-1\cdot\frac{13}{18} \\ E=-0.11 \end{gathered}[/tex]

The expected value is -$0.11.

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