. The r-value for this data is: 2. The classification of this correlation is: 3. The linear equation for this data is: 4. Based on this trend, a 6-foot-9 person will weigh 5. Based on this trend, a 303-pound person's height will be?

The rvalue for this data is 2 The classification of this correlation is 3 The linear equation for this data is 4 Based on this trend a 6foot9 person will weigh class=

Respuesta :

Step 1

Plot the graph of the data provided

Step 2

Find the class for the r-value for this data.

The r-value for this data based on the plot = 0.8482

Step 3

Find the classification of the correlation.

An r-value of 0.8482 is classified as a strong uphill(positive) linear relationship. This shows that there is a strong positive correlation or relationship between the height and weight data given.

Step 3

Find the linear equation for the given data.

[tex]\begin{gathered} \text{The nature of the equation of a line is; y=ax+b} \\ \text{For this data set;} \\ a=4.99642 \\ b=-136.565 \\ \text{Hence, the equation will be;} \\ y=4.99642x-136.565 \end{gathered}[/tex]

Step 4

Based on this trend, a 6-foot-9 person will weigh?

[tex]6-\text{foot}-9\text{ person's height in inches= 81 inches}[/tex]

Substitute 81 inches into the equation

[tex]\begin{gathered} y=4.99642(81)-136.565 \\ y=404.71002-136.565 \\ y=268.14502 \\ y\approx268\text{ pounds to the nearest pounds} \end{gathered}[/tex]

Hence, a 6-foot-9 person will weigh approximately 268 pounds.

Step 5

Based on this trend, a 303-pounds person's height will be?

Substitute 303lb into the equation

[tex]\begin{gathered} 303=4.99642x-136.565 \\ 303+136.565=4.99642x \\ \frac{4.99642x}{4.99642}=\frac{439.565}{4.99642} \\ x=87.97599081 \\ x\approx88\operatorname{cm} \end{gathered}[/tex]

Hence, the height of a 303-pound will be approximately 88cm

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