Question

what is the molarity of a solution of AgNO3 of 98.1 moles of silver nitrate are dissolved to make 0.250L of solution

Answer 1

The molarity or molar concentration is calculted by dividin the number of moles of solute, n, by the total volume of the solution, V, and normally presented in mol/L.

So:

$C=\frac{n}{V}$

We know that the number of moles of AgNO₃ is 98.1 mol and the volume is 0.250 L, so the molarity, C, will be:

$C=\frac{n}{V}=\frac{98.1mol}{0.250L}=392.4mol\/L\approx392mol\/L$

So, the molarity will be approximately 392 mol/L.