Question

|x-3+4=10Ox= -15 and x = 21XOx= -5 and x = -1Ox= 1 and x = 5Ox= 15 and x = 21

Answer 1

SOLUTIONS

Solve for the value of x

$\frac{1}{3}|x-3|+4=10$

Step 1: Subtract the 4 on both side

$\begin{gathered} \frac{1}{3}|x-3|+4=10 \\ \frac{1}{3}|x-3|+4-4=10-4 \\ \frac{1}{3}|x-3|=6 \end{gathered}$

Step 2: Multiply both side by 3

$\begin{gathered} 3.\frac{1}{3}|x-3|=6.3 \\ |x-3|=18 \end{gathered}$

Step 3: Use absolute rule or method and evaluate the x

$\begin{gathered} |u|=a \\ u=-a,oru=a \end{gathered}$

$\begin{gathered} |x-3|=18 \\ x-3=-18,x-3=18 \\ x=-18+3,x=18+3 \\ x=-15,x=21 \end{gathered}$

Therefore the correct answer is

$x=-15,x=21$

Option A