I pointWhich line is parallel to the line given below?І — Зу = 24у = 3х + 8Оy = - x — 4ООООy = — 3х – 1Оy = х + 3

Step 1
Write an expression that allows to known when a line is parallel to another line
[tex]\begin{gathered} \text{For this we use} \\ \text{slope}_1(m_1)=Slope_2(m_2) \end{gathered}[/tex]Step 2
Find the slope of the first(given) line
[tex]\begin{gathered} x-3y\text{ = 24} \\ 3y\text{ = x-24} \\ y\text{ =}\frac{x-24}{3} \\ y\text{ =}\frac{x}{3}-8 \\ \text{Hence, the slope (m}_1)\text{ of the given line is }\frac{1}{3} \end{gathered}[/tex]Step 3
Find the required answer/conclude based on step 2
[tex]\begin{gathered} \text{The only line with an equivalent slope of}\frac{1}{3}\text{ is} \\ y\text{ =}\frac{1}{3}x\text{ + 3} \end{gathered}[/tex]Hence the final answer is option D