Question

Question asks: “Use the table of values to find the derivatives of the following:” In my situation, we are looking at question b.

Answer 1

(a)

$\begin{gathered} f(x)+3h(x)+x^2 \\ at\text{ x=0} \end{gathered}$

then:

$=f(0)+3h(0)+0^2$

the value of f(0) is 4 and h(0) is -1.

$\begin{gathered} =4+3(-1)+0^2 \\ =4-3+0 \\ =1 \end{gathered}$

(b)

$\begin{gathered} \frac{f(x)h(x)}{g(x)}-\frac{2}{x} \\ at\text{ x=1} \end{gathered}$$\begin{gathered} =\frac{f(1)h(1)}{g(1)}-\frac{2}{1} \\ =\frac{0\times2}{4}-2 \\ =0-2 \\ =-2 \end{gathered}$