Question

The ultimate tensile strength of copper is approximately 220 MPa. A material sample with cross-sectional area 0.0022 m^2 would theoretically break under a force of ?

Answer 1

The tensile strenght is given by:

$\sigma_f=\frac{P_f}{A}$

where Pf is the load at fracture, A is the cross section area. Plugging the values given we have:

$\begin{gathered} 220\times10^6=\frac{P^{}_f}{0.0022} \\ P_f=484000 \end{gathered}$

Therefore the force would be 484,000 N.