Question

what's is Brewster's angle for a diamond submerged in water if the light is hitting the diamond (n= 2.42) while traveling in the water?

Answer 1

ANSWER

61.21°

EXPLANATION

The refractive index of water is n = 1.33

In this problem the light travels from water to diamond, so we have to find the angle from the vertical form,

$\tan \theta p=\frac{n_{\text{diamond}}}{n_{\text{water}}}$

Replacing the indices,

$\tan \theta_p=\frac{2.42}{1.33}$

And solving for θ,

$\theta_p=\tan ^{-1}(\frac{2.42}{1.33})$$\theta_p\approx61.21$

Brewster's angle is 61.21°