Question

A figure is made up of two triangles and a square. The trianglesand the square have the same base length of 7 feet. Thetriangles have a height of 5.6 feet. What is the total area of thefigure?

Answer 1

Answer:

Explanation:

Given:

For Triangle:

Height= 5.6 feet

Base= 7 feet

For Square:

Base or side =7 feet

First, we find the area of one of the triangles. We use the formula:

$\begin{gathered} A=\frac{bh}{2} \\ \text{where:} \\ b=\text{base} \\ h=\text{height} \end{gathered}$

We plug in what we know.

$\begin{gathered} A=\frac{bh}{2} \\ =\frac{(7)(5.6)}{2} \\ \text{Calculate} \\ A=19.6in^2 \end{gathered}$

Next, we find the area of the square. We use the formula:

$\begin{gathered} A=s^2 \\ \text{where:} \\ s=\text{side} \end{gathered}$

We plug in what we know.

$\begin{gathered} A=s^2 \\ =(7)^2_{} \\ \text{Calculate} \\ A=49in^2 \end{gathered}$

Then, add the areas together. Remember, there are two triangles. So,

Total Area = 2(Area of Triangle) + Area of Square

= 2(19.6) + 49

=39.2 + 49

Calculate

Total Area = 88.2 in^2

Therefore, the total area of the figure is 88.2 in^2.