Question

Determine the area of Triangle ABC if a = 9, c = 6, and B = 50°. Round your answer to the nearest tenth.

Answer 1

Answer:

20.7

Explanation:

If we have a triangle of the form

then the area is given by

$A=\frac{ab\sin \theta}{2}$

Now in our case we have

a = 6

b = 9

Θ = 50

therefore,

$A=6\cdot\frac{9}{2}\sin 50$

which simplifies to give

$A=27\sin 50$

since

sin 50 = 0.77

the above simplifies to give

$A=27\cdot0.77$$A=20.7$

which is our answer!