The principal amount is
[tex]P=3000[/tex]
The time for which money is borrowed is,
[tex]t=9\text{ months}[/tex]
The interest rate is,
[tex]r=3\frac{1}{2}[/tex]
Determine the time in terms of year by divison of time by 12.
[tex]\begin{gathered} t=\frac{9}{12}\text{ years} \\ =\frac{3}{4}\text{ years.} \end{gathered}[/tex]
The formula for the intrest is,
[tex]I=\frac{P\cdot r\cdot t}{100}[/tex]
Substitute the known calues in the formula to obtain the value of interest.
[tex]\begin{gathered} I=\frac{3000\cdot\frac{3}{4}\cdot3\frac{1}{2}}{100} \\ =\frac{3000\cdot3\cdot7}{2\cdot4\cdot100} \\ =78.75 \end{gathered}[/tex]
So intrest paid by the woman is $78.75.
(b)
Determine the amount paid by the woman.
[tex]\begin{gathered} A=P+I \\ =3000+78.75 \\ =3078.75 \end{gathered}[/tex]
So woman repay $3078.75 to the bank.
