Data:
V= 135π cubic units
d= 18 units
h= ?
The volume of a cone is:
[tex]V=\frac{\pi r^2h}{3}[/tex]As you have the diameter, you find the radius:
[tex]\begin{gathered} r=\frac{d}{2} \\ \\ r=\frac{18u}{2}=9u \end{gathered}[/tex]Solve the equation of volume for h:
[tex]\begin{gathered} V=\frac{\pi r^2h}{3} \\ \\ 3V=\pi r^2h \\ \frac{3V}{\pi r^2}=h \end{gathered}[/tex]Then, the height of the cone is: 5 units
[tex]\begin{gathered} h=\frac{3V}{\pi r^2} \\ \\ ^{}h=\frac{3(135\pi u^3)}{\pi(9u^{})^2}=\frac{405\pi u^3}{81\pi u^2}=5u \end{gathered}[/tex]