Question

Graph a right triangle with two points forming the hypotenuse. Using the sides, find the distance between the two points, to the nearest tenth. (if necessary)(-3,-7) and (2,-3)Find leg number 1 and leg number 2 and the distance

Answer 1

we have that

Leg 1 ------> vertical side

Leg 2 -----> horizontal side

so

Find out the length side Leg 1

Subtract the y-coordinates of the given points (absolute value)

Leg 1=-3-(-7)=-3+7=4 units

Find out the length side Leg 2

Subtract the x-coordinates of the given points (absolute value)

Leg 2=2-(-3)=2+3=5 units

Find out the distance of the hypotenuse

Applying the formula to calculate the distance between two points

$\begin{gathered} d=\sqrt[]{\mleft(-3+7\mright)^2+\mleft(2+3\mright)^2} \\ d=\sqrt[]{16+25} \\ d=\sqrt[]{41} \\ d=6.4\text{ units} \end{gathered}$