The given chemical equation is
[tex]2AgNO_3+BaCl_2\to2AgCl+Ba(NO_3)_2[/tex]
According to the equation, the stoichiometry ratio between AgNO3 and AgCl is 1:1, that is, 1 mole of AgNO3 produces 1 mole of AgCl.
So, use the molar mass of AgNO3 to find the number of moles used in the reaction. (The molar mass of silver nitrate is 169.87 g/mol.
[tex]\text{Moles of }AgNO_3\colon5.0g\cdot\frac{1mol}{169.87g}=0.029mol[/tex]
There are 0.029 moles of AgNO3. Given that the ratio is 1:1, there are produced 0.029 moles of Silver Chloride.
