A survey asked people of different ages whether they get their news byreading the paper. What is the probability that a person surveyed is under 40,given that he or she gets the news by reading the paper? If necessary, roundRead paperDon't readTotalpaperUnder 4043640your answer to the nearest percent.2440 or older1640Total285280

Here, we want to get the probability of A, given B; where A refers to the event that the person surveyed is under 40, and B is the event that he or she gets the news by reading news paper

According to Bayes' theorem, we have the formula to use as;

[tex]P(A|B)\text{ = }\frac{P(AnB)}{P(B)}[/tex]

Since the total is the same, we can work only with the numbers

So, firstly, we need the number of people that gets the news by reading news papers; we have this as 28

Now, we need the number of people who are under 40 and also gets their news by reading papers

We have this as 4

So, we have the probability as;

[tex]P(A|B)\text{ =}\frac{4}{28}\text{ = }\frac{1}{7}\text{ = 14.28 \%}[/tex]

We have this as approximately 14%