Question

Use the diagram to complete the statement.-74A 3G B530)45°C С412/F9ECF=

Answer 1

From the triangle CDF, we can see that it is an isosceles triangle.

$\begin{gathered} \\ \sin \text{ 45 =}\frac{CF}{12\sqrt[]{2}} \\ \frac{1}{\sqrt[]{2}}\text{ = }\frac{CF}{12\sqrt[]{2}} \\ CF\text{ = 12} \end{gathered}$