Given: An animal is running at a rate of 40 ft per sec.
Find: (a) if the animal runs for 5 sec, what is its distance? It’s distance is:
(b)If the animal travels d ft, what is its time?:
Explanation: (a) An animal is running at a rate of 40 ft per sec
if the animal runs for 5 sec then the distance will be
[tex]40\times5=200ft[/tex](b) If the animal travels d ft, then the time will be
[tex]\frac{40}{d}sec[/tex]