Question

How to find the area of different shapes

Answer 1

To answer this question we will use the following formula to compute the area of a trapezoid:

$Area=\frac{(MajorBase+minorbase)height}{2},$

and the following formula to compute the area of a rhombus:

$Area=\frac{MajorDiagonal*minordiagonal}{2}.$

(4) To answer this question we will use the following diagram as a reference:

Using the above diagram we get that:

$\begin{gathered} MajorBase=12m+6m=18m, \\ minorbase=12m, \\ height=8m. \end{gathered}$

Then the area of the trapezoid is:

$Area=\frac{(18m+12m)*8m}{2}=\frac{30m*8m}{2}=120m^2.$

(5) From the given diagram we get:

Then:

$\begin{gathered} MajorBase=7cm, \\ minorbase=4cm, \\ height=3cm. \end{gathered}$

Then, the area of the trapezoid is:

$Area=\frac{(7cm+4cm)*3cm}{2}=\frac{11cm*3cm}{2}=16.5cm^2.$

(6) Notice that the given figure is a rhombus, and its diagonals are:

$\begin{gathered} MajorDiagonal=8ft+9ft=17ft, \\ minordiagonal=6ft+6ft=12ft. \end{gathered}$

Therefore its area is:

$Area=\frac{17ft*12ft}{2}=102ft^2.$

Answer:

$\begin{gathered} 4)\text{ }120m^2. \\ 5)\text{ }16.5cm^2. \\ 6)\text{ }102ft^2. \end{gathered}$