We need to calculate the surface area, the surface area of a prism is given by:
[tex]\begin{gathered} SA=2(lw+lh+wh) \\ w=width=38\frac{3}{8}=\frac{307}{8}_{} \\ l=length=29\frac{1}{2}=\frac{59}{2} \\ h=height=8 \end{gathered}[/tex]
Therefore:
[tex]\begin{gathered} SA=2(\frac{307}{8}\cdot\frac{59}{2}+\frac{59}{2}\cdot8+\frac{307}{8}\cdot8) \\ SA=3350.125ft^2 \end{gathered}[/tex]
If we remove the ceiling and the floor:
[tex]\begin{gathered} SA=3350.125-2(\frac{307}{8}\cdot\frac{59}{2}) \\ SA=1086ft^2 \end{gathered}[/tex]
The painters answer wasn't reasonable at all, they said the area was 542.2ft², which is quite different from 1086ft²