Question

What is the electric force of attraction between charges of+3 C and -6 C separated by a distance of 2 m?

Answer 1

F = k (q1*q2 / r^2 )

Where:

F = electric force

q1 = charge 1

q2= charge 2

r= distance

k = constant= 9 x10^9 Nm^2/C^2

Replacing:

$F=9\cdot10^9\cdot\frac{\parallel3\cdot-6\parallel}{2^2^{}}$

F = 8.1 x 10^10 N