The diagram of the triangle is shown below
Taking 60 degrees as the reference angle,
opposite side = root 3
hypotenuse = 2
We would apply the sine trigonometeric ratio which is expressed as
[tex]\begin{gathered} \sin \emptyset\text{ = opposite side/hypotenuse} \\ \sin \text{ 60 = }\frac{\sqrt[]{3}}{2} \end{gathered}[/tex]