The given triangle is DEF where angle E is a right angle.
The value of DE is 2.1 and EF is 5.3.
As the triangle is a right angle triangle, hence applying the pythagoras theorem,
[tex]\begin{gathered} DF^2=DE^2+EF^2 \\ DF^2=(2.1)^2+(5.3)^2 \\ DF^2=4.41+28.09 \\ DF^2=32.5 \\ DF=\sqrt[]{32.5} \\ DF=5.70 \end{gathered}[/tex]
Thus, the value of the side DF is 5.70 units.
The value of angle D and F can be determined as,
[tex]\begin{gathered} \tan D=\frac{EF}{DE} \\ \tan D=\frac{5.3}{2.1} \\ \angle^{}D=68.38^{\circ} \\ \angle D\approx68^{\circ} \end{gathered}[/tex][tex]undefined[/tex]
