Question

A car moved in positive x direction with an initial velocity of 5 m/s accelerated withuniform acceleration of 1.6 m/s2 to 26.82 m/s. What is the total distance travelled?

Answer 1

ANSWER:

216.97 meters

STEP-BY-STEP EXPLANATION:

From the newton's second law:

$s=\frac{(v^2-u^2)}{2a}$

where v is the final velocity, and the initial velocity and a at the acceleration, we replace:

$\begin{gathered} s=\frac{26.82^2-5^2}{2\cdot1.6} \\ s=216.97\text{ m} \end{gathered}$

The distance traveled is 216.97 meters