Question

7. Solve: 4(x + 3) ≤ 44X ≤ 8X≥ 8x ≥ 16x ≤ 16

Answer 1

We have the following inequality:

$4(x+3)\leq44$

And we have to solve it for x.

To solve the inequality, we can proceed as follows:

1. Apply the distributive property at the left side of the inequality:

$\begin{gathered} 4(x)+4(3)\leq44 \\ \\ 4x+12\leq44 \end{gathered}$

2. Subtract 12 from both sides of the inequality:

$\begin{gathered} 4x+12-12\leq44-12 \\ \\ 4x\leq32 \end{gathered}$

3. Divide both sides of the inequality by 4 as follows:

$\begin{gathered} \frac{4x}{4}\leq\frac{32}{4} \\ \\ x\leq8 \end{gathered}$

Therefore, in summary, the solution for the inequality is:

$x\leq8$

[First option]