If the pace kept was about 7/8 of the intented pace, that means the intended pace is 1 over 7/8 of the pace kept.
So if the pace was 10.4, the intended pace would be:
[tex]\frac{10.4}{\frac{7}{8}}=10.4\cdot\frac{8}{7}=11.886[/tex]So the intended pace is 11.886, therefore the equation would be:
[tex]y=11.886x[/tex]