A quality control inspector has drawn a sample of 20 light bulbs from a recent production lot. Suppose 20% of the bulbs in the lot are defective. What is the probability that less than 8 but more than 4 bulbs from the sample are defective? Round your answer to four decimal places.

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Explanation

We are given a sample 20 bulbs

the percentage of defective = 20% =0.2

So we are told to find the probability that less than 8 but more than 4 bulbs from the sample are defective

[tex]P(4So we will have[tex]P(5)+P(6)+P(7)[/tex]

We will use the binomial probability formula

[tex][/tex]

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