Question

-x²– 3xy + 5y³ : x = - 3, y = - 1

Answer 1

To evaluate the expression when x = -3, and y = -1, we need to substitute these values into the expression, solve the resulting operations, and simplify if necessary. Then, we have:

$-x^2-3xy+5y^3,x=-3,y=-1$

Then, we have:

$-(-3)^2-3(-3)(-1)+5(-1)^3=-9-3(3)+5(-1)=-9-9-5=-23$

Therefore, the value for the evaluated expression when x = -3, and y = -1 is equal to -23.