Given the right angled triangle RST with base 35 and hypotenuse 77.
Using trigonometric ratios,
[tex]\tan \theta=\frac{Adjacent\text{ side}}{Hypotenuse}[/tex]
Plug the given values into the formula.
[tex]\begin{gathered} \tan x^o=\frac{RS}{RT} \\ =\frac{35}{77} \end{gathered}[/tex]
Take inverse of tan on both sides.
[tex]\begin{gathered} x^o=\tan ^{-1}(\frac{35}{77}) \\ =24.444^{\circ} \end{gathered}[/tex]
Rounding to the nearest tenth gives 'x' as 20.
