[tex]x^2\text{ - 2x + 1 = 0}[/tex]
The quadratic formula is given by:
[tex]\frac{-b\text{ + }\pm\text{ }\sqrt[]{b^2-4ac\text{ }}}{2a}[/tex]
Step 1: name the coefficients
a = 1, b = -2, c = 1
Step 2: substitute the vales of the coefficient into the equation
[tex]\frac{-2\text{ }\pm\sqrt[]{(-2)^2\text{ - 4 x 1 x 1}}}{2\text{ x 1}}[/tex]
[tex]\begin{gathered} \frac{-2\text{ }\pm\sqrt[]{4\text{ - 4 }}}{2\text{ x 1}} \\ \\ \frac{-2\text{ }\pm\text{ 0}}{2} \end{gathered}[/tex]
The solution
[tex]\begin{gathered} \frac{-\text{ 2 + 0}}{2}\text{ or }\frac{-2\text{ - 0}}{2} \\ \\ \frac{-2}{2}\text{ or }\frac{-2}{2} \\ \\ -\text{ 1 or -1} \\ \end{gathered}[/tex]
Hence, the solution of the quadratic formula is - 1 (twice)
