To answer this question we need to do a punnets square with the mentioned cross.
P: Tt x tt
The punnet square is as follows
[tex]\begin{bmatrix}{-} & {T} & {t} \\ {t} & {Tt} & {tt} \\ {t} & {Tt} & {tt}\end{bmatrix}[/tex]This way we have two heterozygous and two recessive homozygous, now we proceed to find these proportions. The correct answer is Tt,Tt,tt,tt.