The present question consists of calculating the probability of a randomly picked order to be one of the green ones, it is Accurate or Restaurant A order.
Let's calculate the total number of orders:
[tex]\begin{gathered} N=(320+35)+(265+53)+(247+33)+(126+20) \\ N=355+318+280+146 \\ N=1099 \end{gathered}[/tex]
Now, we calculate the orders which are or from Restaurant A or Accurate.
[tex]\begin{gathered} n=35+320+265+247+126 \\ n=993 \end{gathered}[/tex]
Now, to calculate the probability it, we divide n by N.
[tex]P=\frac{n}{N}=\frac{993}{1099}\cong0.904[/tex]
The probability of the order to be from Restaurant A or Accurate is equal to:
0.904
