Question

An old house in Boxerville measures 40 feet in height and has windows 5-feetin width. An architecture student builds a proportional model that is 6-feethigh. How wide are the model's windows, in feet?

Answer 1

Answer:

$x=0.75\text{ ft}$

Step-by-step explanation:

To solve for the architectural model, use proportional relationships:

$\begin{gathered} \frac{40}{5}=\frac{6}{x};\text{ solve by cross multiplication} \\ x=\frac{6\cdot5}{40} \\ x=\frac{3}{4} \\ x=0.75\text{ ft} \end{gathered}$