Answer
Explanation
Given:
Volume, V = 212 L
Mass of argon = 23300 g
Temperature, T = 25°C = (25 + 273.15 K) = 298.15 K
What to find:
The pressure in the tank.
Step-by-step solution:
The pressure in the tank can be calculated using the ideal gas equation which is:
[tex]PV=nRT[/tex]n is the number of moles and can be also be:
[tex]\begin{gathered} n=\frac{m}{M} \\ \\ Where\text{ }m=mass\text{ }and\text{ }M=molar\text{ }mass \end{gathered}[/tex]Put n = m/M into the ideal gas equation above:
[tex]PV=\frac{m}{M}RT[/tex]The molar mass of argon = 39.948 g/mol
Put the values of the parameterss into the formula to get pressure, P:3
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