Question

find the next 3 terms of geometric sequence 81, 27 9,....

Answer 1

we have

81, 27 9,....​

a geometric sequence

so

a1=81

a2=27

a3=9

a3/a2=9/27=1/3

a2/a1=27/81=1/3

therefore

the common ratio r=1/3

Find out a4

a4=a3*r

a4=9*(1/3)=3

Find out a5

a5=a4*r

a5=3*(1/3)=1

Find out a6

a6=a5*r

a6=1*1/3=1/3

therefore

the next 3 terms of geometric sequence are

3,1,1/3