let assume a number x
According to question Twice a number is more than the sum of that number and 14
So we can write it as:
[tex]2x>x+14[/tex]Solving the above ineqaulity:
[tex]\begin{gathered} 2x>x+14 \\ 2x-x>x-x+14 \\ x>14 \end{gathered}[/tex]So the number should be greater than 14.