the second option is more profitable
if she sells more than $ 18000 per month
Explanation
Step 1
let's check the options we have
a)
one paying $3,000 per month
it means, in a month , she will receive 3.000
[tex]\text{Option}_1=3000[/tex]
b)$2,100 per month plus a 5% commission on all sales made during the month
if x represents the sales, then the formula would be
[tex]\begin{gathered} \text{Option}_2=2100+5\text{ \%(sales)} \\ \text{replacing} \\ \text{Option}_2=2100+0.05x \end{gathered}[/tex]
Step 2
now, to make the option 2 more profitable
[tex]\begin{gathered} \text{option}_1\leq option_2 \\ 3000\leq2100+0.05x \\ \end{gathered}[/tex]
solve for x
[tex]\begin{gathered} 3000\leq2100+0.05x \\ subtract\text{ 2100 in both sides} \\ 3000-2100\leq2100+0.05x-2100 \\ 900\leq0.05x \\ \text{divide both sides by 0.05} \\ \frac{900}{0.05}\leq\frac{0.05}{0.05}x \\ 18000\leq x \end{gathered}[/tex]
therefore, the second option is more profitable
if she sells more than $ 18000 per month
I hope this helps you