Question

Question 37: Find rectangular coordinates for the point with polar coordinates (2, 5π/6).

Answer 1

SOLUTION:

$\begin{gathered} \text{The opposite side of the triangle is }2\sin \frac{\pi}{6} \\ \text{The adjacent side is -2 }\cos \frac{\pi}{6} \end{gathered}$$\begin{gathered} \text{Upon simplification;} \\ x\text{ = -}\sqrt[]{3}\text{ and y = 1} \\ (-\sqrt[\square]{3,}\text{ 1)} \end{gathered}$