It is given that
An aquarium holding African cichlids is 2 inches higher than it is wide. Its length is 32 inches, and its volume is 11520 cubic inches.
Let w be the width of the aquarium.
The height =(w+2) inches
The volume of the aquarium is
[tex]V=\text{width}\times length\times height[/tex]Substitute width=w, height=w+2, length=32 and V=11520, we get
[tex]11520=w\times(w+2)\times32[/tex][tex]11520=32w(w+2)[/tex][tex]11520=32w^2+2\times32w[/tex][tex]11520=32w^2+64w[/tex]Transferring 11520 to the right-hand side, we get
[tex]32w^2+64w-11520=0[/tex]Dividing by 32, we get
[tex]\frac{32w^2}{32}+\frac{64w}{32}-\frac{11520}{32}=\frac{0}{32}[/tex][tex]w^2+2w-360=0[/tex][tex]w^2+20w-18w-360=0\text{ }[/tex][tex]w(w+20)-18(w-20)=0\text{ }[/tex][tex](w+20)(w-18)=0\text{ }[/tex][tex](w+20)=0\text{ or }(w-18)=0[/tex][tex]w=-20\text{ or }w=18[/tex]The measure of side should be positive
We take w=18.
Hence width w=18 inches
Height=w+2=18+2=20 inches .