From the problem, the distance travelled is 720 miles.
Let 2x be the speed of the corporate jet
and
x be the speed of the smaller plane, since smaller plane can fly half as fast as the corporate jet.
Let y be the travel time of the corporate jet
and 6 - y be the travel time of the smaller plane since the total time is 6 hours
The working equation is :
speed x time = distance
For the corporate plane :
[tex]\begin{gathered} \text{speed}\times\text{time}=\text{distance} \\ 2x\mleft(y\mright)=720 \\ 2xy=720 \\ xy=\frac{720}{2}=360 \end{gathered}[/tex]For the smaller plane :
[tex]\begin{gathered} \text{speed}\times\text{time}=\text{distance} \\ x(6-y)=720 \\ 6x-xy=720 \end{gathered}[/tex]Substitute xy = 360 to the 2nd equation :
[tex]\begin{gathered} 6x-xy=720 \\ 6x-360=720 \\ 6x=720-360 \\ 6x=360 \\ x=\frac{360}{6}=60 \end{gathered}[/tex]x = 60 which is the speed of the smaller plane
The speed of the corporate plane will be :
2x = 2(60) = 120
The answer :
corporate jet = 120 mph
smaller plane = 60 mph