Solve the following inequality and enter your answer as an interval

Given the following inequality:
[tex]\frac{9}{2}+x<\frac{22}{18}[/tex]We will solve the inequality as follows, subtract (9/2) from both sides
[tex]\begin{gathered} \frac{9}{2}+x-\frac{9}{2}<\frac{22}{18}-\frac{9}{2} \\ \\ x<\frac{22}{18}-\frac{9}{2} \\ x<-\frac{59}{18} \end{gathered}[/tex]The answer as interval notation will be as follows:
[tex](-\infty,-\frac{59}{18})[/tex]Another method to solve the inequality :
[tex]\frac{9}{2}+x<\frac{22}{18}[/tex]Multiplying both sides by 18:
[tex]\begin{gathered} 18\cdot(\frac{9}{2}+x)<18\cdot\frac{22}{18} \\ 18\cdot\frac{9}{2}+18x<22 \\ 81+18x<22 \\ 18x<22-81 \\ 18x<-59 \\ \\ x<-\frac{59}{18} \end{gathered}[/tex]