Question

f(x)=1/4x^2+bx+10 is x=6. what is the value of b

Answer 1

Given the equation

$f(x)=\frac{1}{4}x^2+bx+10$

For x=6 you have to determine the value of b

To do so, equal the function to zero and replace the variable x with the given number:

$\begin{gathered} \frac{1}{4}(6)^2+6b+10=0 \\ 9+6b+10=0 \\ 6b+19=0 \\ 6b=-19 \\ \frac{6b}{6}=-\frac{19}{6} \\ b=-\frac{19}{6} \end{gathered}$