Answer:
The slope of the line between the two points is;
[tex]m=3[/tex]the slope-intercept form of the line joining the two points is;
[tex]y=3x+2[/tex]Explanation:
Given the points;
[tex]\begin{gathered} (1,5) \\ \text{and} \\ (-2,-4) \end{gathered}[/tex]1.
We want to find the slope, using the coordinates;
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1}=\frac{-4-5}{-2-1}=\frac{-9}{-3} \\ m=3 \end{gathered}[/tex]The slope of the line between the two points is;
[tex]m=3[/tex]2.
Writing the equation in slope-intercept form;
[tex]y=mx+b[/tex]Let us substitute the slope and the coordinates of a point into the point-slope form of a linear equation;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ m=3 \\ (x_1,y_1)=(1,5) \\ y-5=3(x-1) \\ y-5=3x-3 \\ y=3x-3+5 \\ y=3x+2 \end{gathered}[/tex]Therefore, the slope-intercept form of the line joining the two points is;
[tex]y=3x+2[/tex]