Answer:
0.5417
Explanation:
The frictional force is equal to the coefficient of kinetic friction times the normal force, so
[tex]F_f=\mu_kF_n[/tex]Then, solving for the coefficient of kinetic friction, we get:
[tex]\mu_k=\frac{F_f}{F_n}[/tex]Now, we can replace the frictional force Ff by 65 N and the normal force Fn by 120 N
[tex]\mu_k=\frac{65N}{120N}=0.5417[/tex]Therefore, the coefficient of kinetic friction is 0.5417